Problem Statement
Given an array of integers nums
.
A pair (i,j)
is called good if nums[i]
== nums[j]
and i
< j
.
Return the number of good pairs.
Example 1:
Input: nums = [1,2,3,1,1,3] Output: 4 Explanation: There are 4 good pairs (0,3), (0,4), (3,4), (2,5) 0-indexed.
Example 2:
Input: nums = [1,1,1,1] Output: 6 Explanation: Each pair in the array are good.
Example 3:
Input: nums = [1,2,3] Output: 0
Constraints:
1 <= nums.length <= 100
1 <= nums[i] <= 100
Video Tutorial
You can find the detailed video tutorial hereThought Process
Array is the most basic data structures and common solutions inclue
- Nested for loops O(N^2)
- Sort O(NlgN)
- Use extra space O(N)
This applies to this problem perfectly. The O(N^2) brute force solution is naive. We can also use a Map data structure (key is the number, value is the occurrence count) thus O(N). We can also sort the array and use this simple formula (also leetcode's hint) to calculate the good number pair.
Good pairs = N * (N-1) / 2 where N is how many duplicate numbers, this is from combination C(n^2), from n elements pick two
Solutions
Use Map
Space Complexity: O(N) since we use extra Map
Sort
Space Complexity: O(1) no extra space is used
References
- None
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