### Problem Statement

There is a street with `n * 2`

**plots**, where there are `n`

plots on each side of the street. The plots on each side are numbered from `1`

to `n`

. On each plot, a house can be placed.

Return *the number of ways houses can be placed such that no two houses are adjacent to each other on the same side of the street*. Since the answer may be very large, return it **modulo** `10`

.^{9} + 7

Note that if a house is placed on the `i`

plot on one side of the street, a house can also be placed on the ^{th}`i`

plot on the other side of the street.^{th}

**Example 1:**

Input:n = 1Output:4Explanation:Possible arrangements: 1. All plots are empty. 2. A house is placed on one side of the street. 3. A house is placed on the other side of the street. 4. Two houses are placed, one on each side of the street.

**Example 2:**

Input:n = 2Output:9Explanation:The 9 possible arrangements are shown in the diagram above.

**Constraints:**

`1 <= n <= 10`

^{4}

### Video Tutorial

You can find the detailed video tutorial here### Thought Process

- Two sides are independent, each side is similar to Climb Stairs, House Robber House Robber II
- Given each side is independent, the combo would be multiplied together.
- Implementation wise
- could use two variables to replace the array
- be careful about overflow (use long to cast back to int)